The array is failing to display the output in java

import java.lang.*;
import java.util.Scanner;

class Casio
{
	String abc[];
	Scanner j = new Scanner(System.in);
	
	public Casio(int x)
	{
		System.out.println("IM IN DEFAULT CONSTRUCTOR");
		String abc[] = new String[x];
		
		for(int i=0;i<x;i++)
		{
			System.out.println("ENTER THE NAME OF FRIEND "+(i+1));
			abc[i]= j.nextLine();
		}
		
	}
	
	public void show(int q)
	{
		for(int ji=0;ji<q;ji++)
		{
			System.out.println("THE NAMES ARE : "+(abc[ji]));//<-- Error at Line number 27
		}
	}

}

public class mycode
{
	public static void main(String args [])
	{
		int n,q;
		Scanner s = new Scanner(System.in);
		System.out.println("ENTER INITIALIZATION VALUE");
		n = s.nextInt();
		q=n;
		Casio obj = new Casio(n); 
		obj.show(q);//<-- Error at  line number 43
	}
}

THE OUTPUT I GET IS:

Exception in thread “main” java.lang.NullPointerException
at clg.Casio.show(mycode.java:27)
at clg.mycode.main(mycode.java:43)

What I have tried:

When i execute the program . It takes input but it fails to show output. I am trying to take input from array and display output by method calling. please help me. Thank you

——

The Casio constructor creates a local array called “abc” which “hides” the class level version. As a result, the class level version never gets any values assigned to it, or indeed any space for elements.
Change this line:

String abc[] = new String[x];

To this:

abc = new String[x];

And try again.

Seriously, you would have found this very, very quickly if you had used the debugger … it should be your first port of call when you have runtime problems.